Question: Above is an assignment I need help on. I think I have the right answer for #8 (1092351229 + 1460 = 1092352689) but how do

Above is an assignment I need help on. I think I have the right answer for #8 (1092351229 + 1460 = 1092352689) but how do I get the sequence and the length for packet #6. I'm thinking the length would be 1460 but I'm not sure... how do I calculate those two?
Thanks
IP-192.168.0.89 IF-192.168.0.67 IP-192.168.0.89 IP-192.168.0.89 IF-192.160.0.67 IP-192.168.0.67 IP-192.168.0.89 IP-192.168.0.67 IP-192.168.0.67 IP-192.168.0.89 IP-192.168.0.67 IP-192.168.0.67 66 TCP HITP 64 TCP HIT 641 TCP HTTP 369 TCP HTTP 64 TCP BETTP 1518 TCP HTTP 64 TCP HITP 1518 TCP TP 1435 TCP HETP 64 TCP HTTP 1518 TCP HITP 1518 TCP HITP 228701474,L S-1092346931,L O,h 3 IP-192.168.0.67 4 IP-192.168.0.89 5 IP-192.168.0.67 6 IP-192.168,0.67 IP-192.168.0.89 8 IP-192. 168.0.89 9IP-192.168.0.67 10 IP-192.168.0.89 1 IP-192.168.0.89 O,N-8192 o 22870147SM 8760 s- 228701475,LO.A-1092346932,-8760 A. 1092346932 g. 8760 0,A+ 228701786, 8760 S-1092346932,L-1460.A-228701786,T-8760 L 0,h 1092348392,W 8760 S-1092348392,L 1460A- 228701786,8760 -1092349852,L- 1377,h- 228701386,8760 0.h 1092351229, 8760 3-1092351229,L- 1450,A- 228701786- 8760 L-1460 A- 228701786,-8760 S 1092346932,L 228701786,L 12 IP-192.168.0.6 228701786,L 13 IP-192.168.0.89 4 IP-192.168.0.89 1-1460,A- 7. Using the screen capture, write the sequence field for packet 6 8. Using screen capture, write the sequence number for packet #14 9. Using screen capture, write the Length field for packet #6
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