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5) Find: i) the velocity, Vw, of the tungsten ion having kinetic energy Ew=10 keV, and ii) its Larmor radius, pw, corresponding to this velocity, assuming that tungsten ion is completely stripped from electrons and is embedded into a constant magnetic field with the strength B=5 T. (20 points) 5) Find: i) the velocity, VI, of the tritium nucleus having kinetic energy Er=10 keV, and ii) its Larmor radius, PT, corresponding to this velocity, assuming that tritium nucleus is embedded into a constant magnetic field with the strength B=5 T. (20 points) a Solution: i) from the expression for kinetic energy M, V 12 = Eq - Va= V2E,/Ma: converting all units in the Gaussian units we find: VrV2.104.1.6-10-12/3.1.6-10-24 = 0.82-108 cm/s = 0.82-106 m/s. = ii) from L. #4, Eq. (16) we have VI PT eB Converting all units into the Gaussian system we find V Mc PT -0.82-1083.1.6-10-24. 3-1010 -0.5 cm=0.005 m 4.8.10-10.5-104