According to the ideal gas law, a 0.9249 mol sample of xenon gas in a 1.135...
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According to the ideal gas law, a 0.9249 mol sample of xenon gas in a 1.135 L container at 269.1 K should exert a pressure of 17.99 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For Xe gas, a = 4.194 L?atm/mol? and b = 5.105x10-2 L/mol. % Hint: % difference = 100×(P ideal - Pvan der Waals) / P ideal According to the ideal gas law, a 0.9249 mol sample of xenon gas in a 1.135 L container at 269.1 K should exert a pressure of 17.99 atm. By what percent does the pressure calculated using the van der Waals' equation differ from the ideal pressure? For Xe gas, a = 4.194 L?atm/mol? and b = 5.105x10-2 L/mol. % Hint: % difference = 100×(P ideal - Pvan der Waals) / P ideal
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Van der Waals equation an P V2 V nb nRT substituting the values we get 4194... View the full answer
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