In this prelab we will examine the Power of a GPS signal received at your phone...
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In this prelab we will examine the Power of a GPS signal received at your phone and compare it to the thermal noise floor of the phone that normally determines the lowest strength of signal that can be received Thermal Noise Floor - The level of background noise due to being above absolute 0 temperature. The thermal noise power per unit Hertz of frequency bandwidth is given by Thermal Noise Power (Watts/Hz) = Boltzmann's contant(oules temperature (Kelvin) Kelvin (Joules \Kelvin) Boltzmann's contant = 1.38 + 10-23 Let's assume room temperature =16.85C. i. Calculate the thermal noise power in Watts/Hz, dBW/Hz and in dBm/Hz The noise floor due to thermal power for a receiver channel of Bandwidth B is Noise floor due to thermal power = Thermal Power (") - Bandwidth (Hz) GPS operates in the L1 band between 1560 and 1590MHZ centered at 1575.42MHZ +/-1MHZ; that is, the GPS channel's signal main lobe has a bandwidth of 2MHZ ii. Calculate the thermal noise floor of a GPS receiver channel in dBW and dBm A GPS satellite transmits a signal at 478.6W of power at a distance (range) of 20200km from earth Knowing that a GPS channel is centered at 1575.42MHZ and that the speed of an electromagnetic wave is 3x108 meters (meters/second) calculate the wavelength of the GPS signal 2(eers cycle second In one second a GPS signal travels 300 * 10°meters and has 1575.42 + 10°cycles 2 Given that the free space path loss due to spherical spreading = (Wavelength of the signal A(m)) 4+Terange(m) In this prelab we will examine the Power of a GPS signal received at your phone and compare it to the thermal noise floor of the phone that normally determines the lowest strength of signal that can be received Thermal Noise Floor - The level of background noise due to being above absolute 0 temperature. The thermal noise power per unit Hertz of frequency bandwidth is given by Thermal Noise Power (Watts/Hz) = Boltzmann's contant(oules temperature (Kelvin) Kelvin (Joules \Kelvin) Boltzmann's contant = 1.38 + 10-23 Let's assume room temperature =16.85C. i. Calculate the thermal noise power in Watts/Hz, dBW/Hz and in dBm/Hz The noise floor due to thermal power for a receiver channel of Bandwidth B is Noise floor due to thermal power = Thermal Power (") - Bandwidth (Hz) GPS operates in the L1 band between 1560 and 1590MHZ centered at 1575.42MHZ +/-1MHZ; that is, the GPS channel's signal main lobe has a bandwidth of 2MHZ ii. Calculate the thermal noise floor of a GPS receiver channel in dBW and dBm A GPS satellite transmits a signal at 478.6W of power at a distance (range) of 20200km from earth Knowing that a GPS channel is centered at 1575.42MHZ and that the speed of an electromagnetic wave is 3x108 meters (meters/second) calculate the wavelength of the GPS signal 2(eers cycle second In one second a GPS signal travels 300 * 10°meters and has 1575.42 + 10°cycles 2 Given that the free space path loss due to spherical spreading = (Wavelength of the signal A(m)) 4+Terange(m)
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Answer rating: 100% (QA)
Given data Boligmenns domtent K Room timperature T 1685C ... View the full answer
Related Book For
Probability and Statistics
ISBN: 978-0321500465
4th edition
Authors: Morris H. DeGroot, Mark J. Schervish
Posted Date:
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