Acetylene burns in air according to the following equation: CH(g) + O(g) 2C0(g) + HO(g) kJ...

 

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Acetylene burns in air according to the following equation: CH(g) + O(g) 2C0(g) + HO(g) kJ Given AH of CO(g)=-394.4 - and AH of HO(g)=-228.6 mol figures. kJ mol X AH-1256.2 kJ mol find AH of CH(g). Be sure your answer has the correct number of significant Acetylene burns in air according to the following equation: CH(g) + O(g) 2C0(g) + HO(g) kJ Given AH of CO(g)=-394.4 - and AH of HO(g)=-228.6 mol figures. kJ mol X AH-1256.2 kJ mol find AH of CH(g). Be sure your answer has the correct number of significant

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The question presents a chemical equation for the combustion of acetylene C2H2 and provides the enth... View the full answer