Question: Activity Immediate Predecessor Normal Cost (5) Crash Cost (S) Normal Time (days) 4 6 8 4 5 Crash Time (days) 2 4 6 3 2.

Activity Immediate Predecessor Normal Cost (5)

Activity Immediate Predecessor Normal Cost (5) Crash Cost (S) Normal Time (days) 4 6 8 4 5 Crash Time (days) 2 4 6 3 2. B D E A A B C D 1250 1100 600 900 1225 1450 1200 750 1000 1465 The Crashing Cost/Activity for activity "C" is * None of the answers. $100 $57 $75 $50 The "number of activity crashing" for activity "E" is * O 3 hours None of the answers. 3 weeks O 3 months 3 days The project completion time is -------, with a normal cost of 0 21 days; $5,025 21 weeks; $5,025 19 weeks; $5,025 None of the answers. 19 days; $5,075 at an additional crashing To crash the project by 1 day we choose activity cost of None of the answers. D; $75 B; $50 C; $25 A, $100 The new "project cost" is equal to * $5,200 $5,075 $5,125 None of the answers. $5,175 at an additional To crash the project by an additional day, we choose activity crashing cost of None of the answers. O A; $100 B; $50 C; $75 O D; $100 The resulting "project cost" is * None of the answers. $5,225 $5,200 $5,275 $5,175

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