Question: Adding on to the program below, allow the program to read a postfix expression consisting of single digits and operators into a character array. Using

Adding on to the program below, allow the program to read a postfix expression consisting of single digits and operators into a character array. Using the stack functions implemented earlier in the program below, the program should scan the expression and evaluate it.

#include

#include

#include

using namespace std;

string InfixToPostfix(string expression);

int HasHigherPrecedence(char operator1, char operator2);

// Function to verify whether a character is a operator symbol or not.

bool IsOperator(char C);

// Function to verify whether a character is alphanumeric chanaracter (letter or numeric digit) or not.

bool IsOperand(char C);

int main(int argc, char* argv[])

{

system("cls");

string expression;

cout << "Enter Infix Expression ";

getline(cin, expression);

string postfix = InfixToPostfix(expression);

cout << "Output = " << postfix << " ";

system("PAUSE");

return 0;

}

// Function to evaluate postfix expression and return output

string InfixToPostfix(string expression)

{

// Declaring a stack

stack S;

string postfix = ""; // Initializing postfix as empty string.

for (int i = 0; i< expression.length(); i++)

{

if (expression[i] == ' ' || expression[i] == ',') continue;

// If character is operator, pop two elements from stack, perform operation and push the result back.

else if (IsOperator(expression[i]))

{

while (!S.empty() && S.top() != '(' && HasHigherPrecedence(S.top(), expression[i]))

{

postfix += S.top();

S.pop();

}

S.push(expression[i]);

}

// Else if character is an operand

else if (IsOperand(expression[i]))

{

postfix += expression[i];

}

else if (expression[i] == '(')

{

S.push(expression[i]);

}

else if (expression[i] == ')')

{

while (!S.empty() && S.top() != '(') {

postfix += S.top();

S.pop();

}

S.pop();

}

else {

printf("Invalid expression. ");

exit(1);

}

}

while (!S.empty()) {

postfix += S.top();

S.pop();

}

return postfix;

}

bool IsOperand(char C)

{

if (C >= '0' && C <= '9') return true;

if (C >= 'a' && C <= 'z') return true;

if (C >= 'A' && C <= 'Z') return true;

return false;

}

// Function to verify whether a character is operator symbol or not.

bool IsOperator(char C)

{

if (C == '+' || C == '-' || C == '*' || C == '/' || C == '$')

return true;

return false;

}

// Function to verify whether an operator is right associative or not.

int IsRightAssociative(char op)

{

if (op == '$') return true;

return false;

}

int GetOperatorWeight(char op)

{

int weight = -1;

switch (op)

{

case '+':

case '-':

weight = 1;

case '*':

case '/':

weight = 2;

case '$':

weight = 3;

}

return weight;

}

int HasHigherPrecedence(char op1, char op2)

{

int op1Weight = GetOperatorWeight(op1);

int op2Weight = GetOperatorWeight(op2);

if (op1Weight == op2Weight)

{

if (IsRightAssociative(op1)) return false;

else return true;

}

return op1Weight > op2Weight ? true : false;

}

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Databases Questions!