Question: After executing the code on the right what will be the output? String objava is nice System.out.print (obj.charAt(2) * obj.substring, 7). vis is nice vis




After executing the code on the right what will be the output? String objava is nice" System.out.print (obj.charAt(2) "*" obj.substring, 7). vis is nice vis nice After executing the code on the right what will be the content of pos? String 31 - Java is Fun: int pos - 1.IndexOf("Fun"); To check if a string s contains "Java". you write A if (s.substring(0) -- "Java") ... B if (s.charAt(0) "'&& s.charAt(1)|| s.charAt(2) 'V' && s.charAt(3) 'a') Cifts.compareTo("Java") == 0) ... if (5.indexOf("Java") != -1)... What is the output after executing the code below: int x=2, y=2, Z=9; z = x + z/y - 4%; System.out.println(z); What is the output after executing the code below: int y = 8, X- 57 switch (5) case 1: ++ case 2: case 3: Y y + 2; break; case 5: case 7: y - 3 2 System.out.printlnys
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