Question: Again, continuing problem 2 , suppose that you want to force the optional solution to be integers. Do this in Solver by adding a new

Again, continuing problem 2, suppose that you want to force the optional solution to be integers. Do this in Solver by adding a new constraint. Select the decision variable cells for the left side of the constraint, and in the middle dropdown list, select the int option. How does the optimal integer solution compare to the optimal noninteger solution in problem 2? Are the decision variable cell values rounded versions of those in problem 2? Is the objective value more or less than in problem 2? Please help ASAP and add pictures!
\table[[,A,B,C,D,E],[1,Building PCs,,,,],[2,,,,,],[3,Labor cost/hr assembly,$11,,,],[4,Labor cost/hr testing,$15,,,],[5,,,,,],[6,Input,,,,],[7,,PC1,PC2,PC3,],[8,Labor hrs.(assembly),5,6,8,],[9,Labor hrs.(testing),1,2,3,],[10,Cost of hardware,$150,$225,275,],[11,Selling price,$300,$450,560,],[12,Test profit,$80,$129,$152,],[13,,,,,],[14,Testing profit model,,,,],[15,,PC1,PC2,PC3,],[16,Production quantity,514,1200,29,],[17,,=,=,,]]
\table[[18,Maximum sales,600,1200,50,],[19,,,,,,,],[20,Constraints (monthly hrs.),Hours used,,Hours available,,,],[21,Assembly labor usage,10002,=,10000,,,],[22,Testing labor usage,3001,=,3000,,,],[23,,,,,,,],[24,Net total profit,PC1,PC2,PC3,Total,,],[25,,$41,120,$154,800,$4,408,$200,328,,]]
 Again, continuing problem 2, suppose that you want to force the

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