Question: ah! based on that definition, if g(t) = W(t) * e^[(from t_0 to t) tr(A(s)) ds] then g'(t) = [W'(t)-W(t)trA(t)] * e^[(from t_0 to t)

ah! based on that definition, if g(t) = W(t) * e^[(from t_0 to t) tr(A(s)) ds] then g'(t) = [W'(t)-W(t)trA(t)] * e^[(from t_0 to t) tr(A(s)) ds] which would then = 0 since W'(t) = tr(A(t)) * W(t)

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!