Question: aj 40-0 tan e Sen = Cos tan e = 012/812 COS (90-0) sen (90-0) a cot (90-8) = cot (90-0)= = 916 old

aj 40-0 tan e Sen = Cos tan e = 012/812 COS

aj 40-0 tan e Sen = Cos tan e = 012/812 COS (90-0) sen (90-0) a cot (90-8) = cot (90-0)= = 916 old cot (90-9)=tane f) sin 45+ cos 45 false Sin 45 = cos 45- = 1" 2 + 22 = = 2 2 Sin4scos 45 = 2 2

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