Algorithms and Data Stuructue.

Please code with C language.

I added an example to help

1. LABORATORY WORK NI. Algorithms with branches The purpose of laboratory work Purpose of laboratory work Nel "Branched Algorithms" is mastering the theoretical material and gaining the practical skills in the use of branching structures and boolean (logical) operations Purpose of laboratory work Purpose of laboratory work Nel Algorithms with Branches is mastering theoretical material and gaining practical skills in the use of branching control structures and boolean (logical) operations Formulation of the problem A valid number x is specified. Determine the value of an alternatively piecewise continuous function y(x), if any, or display a non-existent function message for a given x There are two ways to solve this problem (write two programs): 1) only single comparison operations (,, >=) are allowed in the program and Boolean (logical) operations (not, and, or, etc.) are not allowed; 2) Boolean (logical) operations (not, and, or, etc.) must be used in the program, the use of boolean operations should not be excessive. Contents of the report 1. General task statement and task for a particular variant. 2. Texts of both programs 3. Flowcharts of both programs. 4. Testing results for both programs. When testing each of the programs it is necessary to select such a set of input values of x so that the correctness of all branches of the algorithms is tested. 5. As a result, print the test data for all input values from the test set for each program individually. 6. Conclusions including the essence of the investigated algorithm with branches An example of a flowchart with conditional constructions is the following. Problem: Find the maximum of three numbers a, b, c, Flowchart: Begin Input a,b,c 06 0 a>b 1 0 1 a> C>b Output a Output Output b END On the program in the structural style is: #include int main() float a,b,c; scanf("%f%f%f",&a,&b,&c): if (a >b) if (a>c) printf("MAX %f ".a); else printf("MAX C-%fn",c); else if (c > b) printf("MAX c%f ".c); else printf("MAX b-%fn",b); retum 0: } Variant 10 3 S -5x + 10, y = 2x} + 8x?, xe[8, 23] xe(-2, -19) [- 3, 0]