An accelerated electron

An electron is initially at rest. At time t$\_(1)=0$ it is accelerated upward with an acceleration of a$=1\backslash$times $10^(19)($m$)/($s$^(2))$ for a very short time

$($this large acceleration is possible because the electron has a very small mass$).$ We make observations at location A$,$x$=18$ meters

from the electron $($see the figure$).($b$)$ At what time $\backslash ($ t$\_\{3\}\backslash )$ does the electric field at location $\backslash ($ A $\backslash )$ change?seconds

$($c$)$ What is the direction of the electric field at location $\backslash ($ A $\backslash )$ at time $\backslash ($ t$\_\{3\}\backslash )?$

zero field

upward

downward

to the right

to the left

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Part $3$

$($d$)$ What is the magnitude of this electric field?

N$/$C

$($e$)$ A positively charged particle was initially at rest at location $\backslash ($ A $\backslash ).$ It is released from rest just after time $\backslash ($ t$\_\{3\}\backslash ).$ Which of the following are true just after time $\backslash ($ t$\_\{3\}\backslash )?($Select all that apply.$)$

The electric force on the positive charge is toward the electron.

There is a magnetic force to the right on the positive charge.

The positive charge begins to move because there is a force on it due to the radiative electric field.

The radiative magnetic field at location $\backslash ($ A $\backslash )$ is out of the page.

The positive charge will never be affected by the radiative magnetic field, since the positive charge is always at rest.

The electric force on the positive charge due to the radiative electric field is upward.