Question: An algorithm has a worst-case time complexity given by the following recurrence relation: T(n) = T(n-1) + 4n^2 + c2 for n > 0, and

An algorithm has a worst-case time complexity given by the following recurrence relation: T(n) = T(n-1) + 4n^2 + c2 for n > 0, and T(0) = c1. C1 and C2 are constants. Solve the recurrence relation T(n), and give its order using Big Oh notation. You must explain how the recurrence relation was solved.

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