An aluminum target (27Al) having an area of 1 cm and a thickness of 0.1 cm...

Transcribed Image Text:

An aluminum target (27Al) having an area of 1 cm and a thickness of 0.1 cm is bombared by a monoenergetic neutron beam with an intensity of 1E10 neutrons/cmsec to produce 28 Al (T1/2 = 2.3 min). 28 Al decays into 28 Si which is stable. Calculate the mass of 28 Si 5 minutes after the start of the activation. You should write the relevant differential equations and solve them. Al-27=0.01386 cm (related to activation of Al-27) Atomic weight of Si-28 = 28 An aluminum target (27Al) having an area of 1 cm and a thickness of 0.1 cm is bombared by a monoenergetic neutron beam with an intensity of 1E10 neutrons/cmsec to produce 28 Al (T1/2 = 2.3 min). 28 Al decays into 28 Si which is stable. Calculate the mass of 28 Si 5 minutes after the start of the activation. You should write the relevant differential equations and solve them. Al-27=0.01386 cm (related to activation of Al-27) Atomic weight of Si-28 = 28