An analytics company sampled 9090 online meetings and found the meetings to have an average duration...
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An analytics company sampled 9090 online meetings and found the meetings to have an average duration of 9090 minutes with a standard deviation of 9090 minutes. It is further known that the probability that the average meeting duration is longer than xx is 0.98260.9826 i.e., P(Xxx)=0.9826P(Xx=0.9826. Calculate the value of xx and choose the correct answer from the list of options below. a. 64.9564.95 minutes b. 97.9797.97 minutes c. 80.0480.04 minutes d. 69.9869.98 minutes e. 95.0395.03 minutes An analytics company sampled 9090 online meetings and found the meetings to have an average duration of 9090 minutes with a standard deviation of 9090 minutes. It is further known that the probability that the average meeting duration is longer than xx is 0.98260.9826 i.e., P(Xxx)=0.9826P(Xx=0.9826. Calculate the value of xx and choose the correct answer from the list of options below. a. 64.9564.95 minutes b. 97.9797.97 minutes c. 80.0480.04 minutes d. 69.9869.98 minutes e. 95.0395.03 minutes
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