Question: An array A [ 1 dotsn ] is said to have a majority element if more than half of its entries are the same. Given

An array A[1dotsn] is said to have a majority element if more than half of its entries are the same. Given an array, the task is to design an efficient algorithm to tell whether the array has a majority element, and, if so, to find that element. The elements of the array are not necessarily from some ordered domain like the integers, and so there can be no comparisons of the form "is A[i]>A[i]?".(Think of the array elements as GIF files, say.) However, you can answer questions of the form: "is A[i]=A[i]?" in constant time.
(a) Show how to solve this problem in O(nlogn) time. (Hint: Split the array A into two arrays A1 and A2 of half the size. Does knowing the majority elements of A1 and A2 help you figure out the majority element of A? If so, you can use a divide-and-conquer approach.)
(b) Can you give a linear-time algorithm? (Hint: Here's another divide-and-conquer approach:
Pair up the elements of A arbitrarily, to get n2 pairs.
Look at each pair: if the two elements are different. discard both of them; if they are the same, keep just one of them.
Show that after this procedure there are at most n2 elements left, and that they have a majority element if and only if A does.)
 An array A[1dotsn] is said to have a majority element if

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