An electron, initially at rest, is accelerated by a $12$ kV accelerating potential $($i$.$e$.,$ placed in an electric field such that the electron accelerates from an original position to a second position at a potential $12kV$ higher than the original$).$ Utilize the mass of the electron as $9\mathrm{.}1{10}^{-31}kg.$ What is the final speed of the electron?

Hint: Calculate the initial electric potential energy, then use the law of conservation of energy to determine the electron's kinetic energy

$6\mathrm{.}5{10}^7\frac{m}{s}$

$3\mathrm{.}5{10}^7\frac{m}{s}$

$3\mathrm{.}5{10}^5\frac{m}{s}$

$6\mathrm{.}5{10}^3\frac{m}{s}$