An electron that has velocity v$=(2\mathrm{.}0$x$10^6$m$/$s$)$i$+(3\mathrm{.}0$x$10^8$m$/$s$)$j moves through the uniform

magnetic field B$=0\mathrm{.}030$Ti$-0\mathrm{.}15$Tj $($a$)$ Find the force on the electron due to the magnetic field.

$($b$)$ Repeat your calculation for a proton having the same velocity.