An equilibrium ore mixture has atom ratio for $235$U$/231$Pa of $2\mathrm{.}33$x$10\mathrm{⁴}.$ What is the half$-$life of $235$U from the data, given that the half$-$life of $231$Pa is $3\mathrm{.}28$x$10\mathrm{⁴}$ years. 

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To find the halflife of 235U we can use the concept of radioactive decay and t... View the full answer