An exercise working with a 2-dimensional array. Do the following: 1. Display the 2-D array so the rows are left justified. Use a nested for-loop. System.out.printf("%4d", array2D[ rowIndex][columnIndex]) 2. Compute and display the total number of array elements. This requires a simple for-loop to sum the row lengths. System.out.printf("Total number of array elements: %d ", total); a. After the above logic is correct, add logic to find the longest row and its row index. 3. Sum all the array elements and display the total. This requires a nested for-loop. System.out.printf("Sum of all the array elements: %d ", total); 4. Prompt the user for a column index. Display the column, one number per line. Display the word "empty" when the column value is missing. o System.out.print(" Enter a column to display: "); o System.out.printf("%d ", array20[rowIndex][columnIndex]); System.out.println("empty"); Get started with the supplied template. import java.util.Scanner; public class Array20 { public static void main(String[] args) { int ir, ic; // loop counters. Scanner console new Scanner(System.in); int [][] array2D={{7, 2, 9, 8), // row e, columns @ to 3 (6, 5, 4, 0, 2), // row 1, columns @ to 5 {(1, 2, 3 }); // row 2, columns 0 to 2 // 1. Display all 2-D array elements as a left justified table // System.out.printf("%4d", array2D [rowIndex][columnIndex]); // 2. Display the number of array elements. Add logic to find the // longest row. /" int total = 0; // running sum total int longRow= 0; "/ // this is the length of the longest row System.out.printf("Total number of array elements: %d ", total ); "/ // 3. Sum all array elements and display the total: // System.out.printf("Sum of all the array elements: %d ", total); // 4. Select and display a column given its index: /" System.out.print(" Enter a column index to display: "); console.nextInt(); ic ic = Math.min( longRow-1, Math.max(ic, 0)); System.out.printf("%d ", array2D[rowIndex][columnIndex]); System.out.println("empty"); } // end main // end class