An independent samples t-test is computed to examine the difference in symptoms of anxiety in two samples.One group was the control group (sample 2) and one group was the experimental group (sample 1).The researchers hypothesized that the experimental group would demonstrateLOWER symptoms of anxiety(lower mean scores) at the end of the study.

Sample 1

26 (n)

25 (df)

37 (M)

4 (s)

400 (SS)

Sample 2

101 (n)

100 (df)

40 (M)

3 (s)

900 (SS)

1a. What is thepooled df?(1/2 point)

The Pooled df is 100+25=125

1b. Now that we know the pooled df, we can find the t_criticalcut-off value. Assume this is a one-tailed test with = .05.

1c. Calculate the pooled variance.

1d. Now that you have the pooled variance, calculate theestimated standard errorof mean differences.

7(2)/26+7(2)101=

0.53+0.13=0.66

1e. Now that you know the "normal difference" between M₁and M₂(estimated standard error of mean differences. Calculate t.

T= ((M₁-M₂)- (₁-₂))/ (S_(M1-M2))=

1f. Can we reject the null hypothesis (H₀)?

Can reject the null hypothesis