Question: An infinitely deep square well has width L = 2.5 nm. The potential energy is V = 0 eV inside the well ( i.e. ,

An infinitely deep square well has width L = 2.5 nm. The potential energy is V = 0 eV inside the well ( i.e. , for 0 ≤ x ≤ L ). Seven electrons are trapped in the well.

1) What is the ground state (lowest) energy of this seven electron system in eV?

E _ground =

2) What is the energy of the first excited state of the system in eV?

NOTE: The first excited state is the one that has the lowest energy that is larger than the ground state energy.

E _excited =

3) What is the energy of the second excited state of the system in eV?

E _second =

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