Question: An intermediate communication node receives data packets from a number of user - nodes on campus at rate 6 8 per second and then transmits

An intermediate communication node receives data packets from a number of user-nodes on campus at rate 68 per second and then transmits them to the external network. The time to transmit one packet is proportional to packet size, and on average is 7.4 milliseconds (millisecond is 0.001 of a second). Packets are transmitted one at a time. Due to sensitive applications, the users require an accurate estimate for the delay due to waiting at the intermediate node. In the current implementation, the users are provided with the delay value calculated based on M/M/1 model for the queue at the intermediate node. After careful examination of the system you noticed that while the average time to transmit one packet is 7.4 milliseconds, its standard deviation is in fact 4.4 milliseconds, meaning that the transmission time is not exponential. Calculate the error in the average transmission delay
due to the incorrect assumption. Express it in milliseconds. Hints: - think carefully if you are interested in W or WQ values - to calculate the error, first, find the delay in the M/M/1 system, then decide what kind of queue the real system is and then calculate the delay in it and finally find the difference. - remember that for any random variable: E[S2]=(E[S])2+ 2(S).

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