An ionised Lithium atom is placed at point A, close to the positive end of a charged capacitor; initially at rest with a potential value of VA. The particle is accelerated away from the positively charged plate towards the negatively charged plate to point B, a small hole in the capacitor with potential VB. As it leaves the capacitor, it enters a magnetic field of strength B = 0.250 T, directed perpendicular to the velocity and pointed outwards from the paper, and bends around to a detector placed in the correct position. If the potential difference VA - VB = 4180 V, the mass of a lithium nucleus is m = 1.00 x 10-26 kg, and the charge is q = +3e, where e = 1.60 x 10-19 C. (a) Using the conservation of energy, find the speed of the particle as it leaves the capacitor. (b) Using the appropriate right-hand-rule, which direction does the particle deflect in the magnetic field? (c) What is the magnetic force that acts on the particle? (d) What is the radius of the circle of the resulting uniform circular motion that the particle exhibits? O 180 V 10 - 20 Ky B . 10 - 19 ( A + .+ + + + + + + + + + +