An L x W rectangular block of material, where L = 37.6 cm and W =...

   

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An L x W rectangular block of material, where L = 37.6 cm and W = 26.4 cm, has mass Mblock = 5.63 kg. A lightweight thin hoop of radius R = 26.7 cm has mass Mhoop = 0.325 kg. Using wires of negligible mass, the block is attached to the hoop such that their centers are at a common point. The composite object is placed upon an inclined plane that makes an angle = 22.1 with the horizontal, as shown. After being released from rest, the composite object rolls without slipping down the incline for a distance d = 2.31 m parallel to the surface. Myop Mblock 0 In general, the MOI of a composite object may oftentimes be computed by summing the MOIS of more simple objects, and sometimes the Parallel Axis Theorem is required. In lieu of the typical table as found in most textbooks, the MOIS of uniform standard objects may be obtained by using the left and right arrows to step through the image carousel to the right. 5/11 thin rod, perpendicular to rotation axis at one end M L What is the final speed, in meters per second, of the composite object? m/s V = sin() cotan() atan() cosh() cos() asin() acotan() tanh() O Degrees Submit tan() acos() E sinh() cotanh() Radians Hint Hints: 3 for a 0% deduction. Hints remaining: 0 -How much gravitational potential energy has been converted to kinetic energy when the composite object has traveled a distance d? The change in height may be obtained using trigonometry. -The kinetic energy has both a rotational and a translational component. You will need to eliminate the angular velocity in favor of the linear velocity. -Obtain the formulas for the MOIS of the separate constituents from the image. carousel in the problem statement. Decide whether the MOIS are okay as presented, or if the Parallel Axis Theorem is required. C ) 1 + 7 4 1 2 0 BACKSPACE DEL Feedback ** 8 9 5 6 3 - HOME END CLEAR I give up! Feedback: 0% deduction per feedback. An L x W rectangular block of material, where L = 37.6 cm and W = 26.4 cm, has mass Mblock = 5.63 kg. A lightweight thin hoop of radius R = 26.7 cm has mass Mhoop = 0.325 kg. Using wires of negligible mass, the block is attached to the hoop such that their centers are at a common point. The composite object is placed upon an inclined plane that makes an angle = 22.1 with the horizontal, as shown. After being released from rest, the composite object rolls without slipping down the incline for a distance d = 2.31 m parallel to the surface. Myop Mblock 0 In general, the MOI of a composite object may oftentimes be computed by summing the MOIS of more simple objects, and sometimes the Parallel Axis Theorem is required. In lieu of the typical table as found in most textbooks, the MOIS of uniform standard objects may be obtained by using the left and right arrows to step through the image carousel to the right. 5/11 thin rod, perpendicular to rotation axis at one end M L What is the final speed, in meters per second, of the composite object? m/s V = sin() cotan() atan() cosh() cos() asin() acotan() tanh() O Degrees Submit tan() acos() E sinh() cotanh() Radians Hint Hints: 3 for a 0% deduction. Hints remaining: 0 -How much gravitational potential energy has been converted to kinetic energy when the composite object has traveled a distance d? The change in height may be obtained using trigonometry. -The kinetic energy has both a rotational and a translational component. You will need to eliminate the angular velocity in favor of the linear velocity. -Obtain the formulas for the MOIS of the separate constituents from the image. carousel in the problem statement. Decide whether the MOIS are okay as presented, or if the Parallel Axis Theorem is required. C ) 1 + 7 4 1 2 0 BACKSPACE DEL Feedback ** 8 9 5 6 3 - HOME END CLEAR I give up! Feedback: 0% deduction per feedback.

Answer rating: 100% (QA)

To find the final speed v of the composite object at the bottom of the incline we can apply the conservation of energy principle Specifically the init... View the full answer