Question: An object is placed 2 0 . 0 cm to the left of a converging lens that has a focal length f 1 = +
An object is placed cm to the left of a converging lens that has a focal length How far is the image from the lens? Give your answer to at least one decimal place.
cm
A screen is placed cm to the right of the converging lens. A diverging lens is placed between the converging lens and the screen. When the diverging lens is cm to the right of the converging lens the image formed by the lens combination is located at the screen. What is the focal length of the diverging lens?
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