Question: An object thrown vertically upward from the surface of a celestial body at a velocity of 32 mis reaches a height of s = -

An object thrown vertically upward from the surface of a celestial

An object thrown vertically upward from the surface of a celestial body at a velocity of 32 mis reaches a height of s = - 0.8+32t meters in t seconds. a. Determine the velocity v of the object after t seconds. b. When does the object reach its highest point? c. What is the height of the object at the highest point? . When does the object strike the ground? e. With what velocity does the object strike the ground? 1. On what intervals is the speed increasing? a. The object's velocity after t seconds is v(1) =

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