Question: Analyze the following code: Code 1 : number = eval ( input ( Enter number: ) ) if number % 2 = =

Analyze the following code:
Code 1:
number = eval(input("Enter number: "))
if number %2==0:
even = True
else:
even = False
Code 2:
number = eval(input("Enter number: "))
even = number %2==0
Group of answer choices
Code 1 has compile errors.
Code 2 has compile errors.
Both Code 1 and Code 2 have compile errors.
Both Code 1 and Code 2 are correct

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