Angle

C=90I^()

in a right spherical triangle

ABC

. If

C=80

and

a=50I^()

,\ fincl b in dgrees.\ use Napier's circle equation:\

C

as the middle part:\

sinC=cosaxcosb

\ A.

70.35(1)/(2)

\

cosc=cosaxcosb

.\ B.

75.63(1)/(5)

\ C.

73.55(1)/(2)

\ (D.)

74.33(1)/(2)

Angle C=90I in a right spherical triangle ABC. If C=80 and a=50I, find b in dgrees. use Napier's circle equation: C as the middle part: Sin c=cosaxcosb A. 70.3521 cosc=cosaxcosb. B. 75.6331 C. 73.5521 (D.) 74.3321