Ans is $0\mathrm{.}0056$m$^3/$s show all steps please. A sump pump is used to pump water $(\{$:$=1000\frac{kg}{m^3},=1{10}^{-3}(Pa)*s)$ from a collection

basin in the basement of a house away from the foundation. The installation shown below uses

$15m$ of $4cm$ diameter galvanized iron pipe with two threaded $90$ smooth bends and a reentrant

inlet to raise the water to a height of $H=8m.$ The pump characteristic curve can be approximated

by $h_p=45-4000V^{},$ where $V^{}$ is in $\frac{m^3}{s}$ and $h_p$ is in $m.$ Water in the basin is open to

atmosphere and is discharged to atmospheric pressure outside of the house. The cross$-$sectional

area of the basin is much larger than that of the pipe. Accounting for both pipe losses and minor

losses, calculate the volume flow rate of water that the system can remove.