Question: In an isosceles right angled triangle ABC, ZB = 90, AD is the median, then sin ZBAD sin ZCAD is: (A) + (B) V2

In an isosceles right angled triangle ABC, ZB = 90, AD is 

In an isosceles right angled triangle ABC, ZB = 90, AD is the median, then sin ZBAD sin ZCAD is: (A) + (B) V2 (C) 1 (D)

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