Answer all 3 questionsMean= 5Standard deviation= 0.02

(b) Any ball bearings that have a diameter less than 4.95 mm or greater than 5.05 mm are 4:95- 5 discarded. What proportion of ball bearings will be discarded? Show calculation. 0.02 - - 2.5 2= 5,05-5 0.02 = 2.5 P( x 2 4,95 ) = 0.0062 P (x 2 5. 05 ) = 1- 0.9938 =0 P ( 4.95 > > > 5.05 ) = 0.0124 (c) Using the results of part (b), if 30,000 ball bearings are manufactured in a day, how many should the plant manager expect to discard? Show calculation. 30, 000 x 0,0124= 372 bearings (d) If an order comes in for 50,000 ball bearings, how many ball bearings should the plant manager manufacture if the order states that all ball bearings must be between 4.97 mm and 5.03 mm? Show calculation