Question: answer d e Question 2. The motion of an object subject to friction is described with the following 1 st order ODE. mdtdv+fv=f(t) The value

answer d e
answer d e Question 2. The motion of an object subject to
friction is described with the following 1 st order ODE. mdtdv+fv=f(t) The

Question 2. The motion of an object subject to friction is described with the following 1 st order ODE. mdtdv+fv=f(t) The value of m=80kg and f=12skg. Here, the forcing function has dimensions of force (which has units of N or kgs2m ) a. (1 point) What is the time constant () associated with the system? Use correct units. b. (1 point) What is the gain (K) associated with the function? Use correct units. c. (1 point) If f(t)=7N, what is v(t) when the system is at steady-state? Use correct units. d. (1 point) If f(t) suddenly changes from f(t)=2N to f(t)=25N, how long will it take for v(t) to reach its new steady-state value? Use correct units. Explain how you arrived at this answer. e. (1 point) A sinusoidal driving force is applied so that the forcing function is now f(t)=Fcsin(100t/), where is the time constant that you calculated in (a). What is the amplitude of v(t) at steady-state? Choose the best answer. Note that K refers to the system gain that you calculated in (b). Briefly explain how you arrived at your answer. a. Amplitude =KFc b. Amplitude >KFc c. Amplitude

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