Question: 4. If tane=ntano then the maximum value of tan (0-0) is equal to (n+1) 2n 5. 1) (n+1) 4n The value of cot- of

4. If tane=ntano then the maximum value of tan (0-0) is equal to (n+1) 2n 5. 1) (n+1) 4n The value of cot- of 7T =d16 1 and 3 is 2) +2 cot- (n-1) 4n 3 8 2) 2 1) 4 6. If tan0=2 tan+1, then cos 20+sin o equals 2) 0 28 15t 16 + cot- is 1)-1 shou 3) 1 4) 2 7. Given that a,b,c are the sides of a AABC which is right angled at vertex C, then the minimum val 163) k=1 10. If cos(A+B+C) = cos Acos B cos C, then 1) -sin(101x) 101 2 3)-2 1) 0 2) 8 3) 22 4) 2 8. In triangle ABC, if angle C is 900 and the area of triangle is 30 sq. units, then the minimum possi value of the hypotenuse c is equal to (in units) 1) 30-2 2) 602 4) 3) 1202 4) 230 9. In a right angled triangle the hypotenuse is 22 times the perpendicular drawn from the opposi vertex. Then the other acute angles of the triangle are TU (2) TC TL 3 and 8 8 TU 3) and 101 4 (n-1) 2n 4)-4 8 sin(B+C) sin(C+4) sin(A + B) sin 24 sin 2Bsin 2C 3) 1/2 1) 1 2) -1 4) -1/2 11. The sum of the series, sin 0 sec(30)+sin 30 sec(320)+sin(320) sec (30)+.... upto n terms, is 1) [tan 3"0-tan 3"-0] 2) [tan 3"0-tan 0] 4) (tan 3" 0-1) 1 [tan 3"0-tan 0] 1 TO 4) and 5 12. If c.B.7 are acute angles and cos 0 = sin/sina, cos o sin y/sina and cos(0-0)=sin siny the the value of tan a-tan -tany is equal to 1) -1 2) 0 3 10 3) 1 4) 2 13. Let o.B, andy satisfy 0
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