Question: Answer & explanation Generated by AI Here's the solution for the given problem: java for ( int i = 0 ; i < myStringArray.length; i
Answer & explanation
Generated by AI
Here's the solution for the given problem:
java
for int i ; i myStringArray.length; i System.out.printmyStringArrayi; System.out.printlnCompleted;
Stepbystep Explanation:
Loop Initialization: int i starts the loop at the first index of the array.
Loop Condition: i myStringArray.length keeps the loop running as long as i is less than the length of the array, ensuring all elements are accessed.
Loop Increment: i increases i by with each iteration, progressing through each array element.
Print Statement: System.out.printmyStringArrayi outputs each element in the array followed by a space. This keeps all elements on the same line.
Completion Message: After the loop ends, System.out.printlnCompleted prints "Completed" on a new line.
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