Question: answer In 48 and 49 below, a logical equivalence is derived from Theorem 2.1.1. Supply a reason for each step. 48. (p A ~q) V

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answer In 48 and 49 below, a logical equivalence
In 48 and 49 below, a logical equivalence is derived from Theorem 2.1.1. Supply a reason for each step. 48. (p A ~q) V (pq) = p/(~qvq) by (a) =pA (q v ~q) by (b) =pAt by (c) =P by (d) Therefore, (p A ~q) V (p q) = p

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