Question: answer me fast plz A Mandom sample of, size 1 wor taken from normal population jobded the mean an 19 with old deviation 4- prothe

answer me fast plz

answer me fast plz A Mandom sample of, size 1 wor taken

A Mandom sample of, size 1 wor taken from normal population jobded the mean an 19 with old deviation 4- prothe zandorn samph of size 25 from the normal population gave mean al 23 and Eid deviation 01 25 then the 901. confidence interval toy difference between two means is In RBD. performed with & Treatment applied in & blocks had one musing you'd Ol, The Guruand total without missing yield is 365 3 second block talk without mining yield in 68 4, and second twatment total without miking yold in 50-q, then the estimate of missing bold it (6 15 35 (2) 14.25 0)1-50 The ANOVA TABLE of wxy 150 a quen bday (141.52 SV SS. RAUH 259-5395 3 155- 2975 3 156-3700 Then, the mean fum of square due to treatment for the quand fatal and fum of squmu of observation mentioned below is 41 (1-360 2 (EXi) = 10952-09 0)557-4257 (6) 459-3942 (2) 754-7342 (D) 157 . 2732 D In (NPD) factor s level factorial experiount, if the Itematment sum of squares for main effect of mis 3619 .5 and eases sam of squares is 7539.0 ,then calculated value of Fir (@) 3 42 (6) 2-34 (0)4.32 (d)9-23 The A random sample of size i was taken from following probability density function of a random variable X and the observations are 0 . 14 , 0.25, 0:36, 0.82, 0.32, 0.40, 0-11 f (x, D) = 1, Dexo, " the mule' of 9 1 (a) 0 82 (6) 0 .72 20.62 (d)0.38

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