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Question 1 (Mandatory) (2 points) Assume that the tip of your buret was not properly filled with NaOH solution. [t contained an air bubble which was eliminated during the titration. Would the calculated molarity of the vinegar be smaller, larger, or that same as the true molarity? Why? '3::_:3' a) The calculated molarity of the vinegar would be larger than it should be. Some of the NaOH was used to fill the volume of the air bubble. Thus, the recorded volume of NaOH is larger than it would have been in the absence of an air bubble. '3:___:3' b) The calculated molarity of the vinegar would be smaller than it should be. Some of the NaOH was used to fill the volume of the air bubble. Thus, the recorded volume of NaOH is larger than it would have been in the absence of an air bubble. _ c) The calculated molarity of the vinegar would be larger than it should be. Some of the NaOH was used to fill the volume of the air bubble. Thus, the recorded volume of NaOH is smaller than it would have been in the absence of an air bubble. B ./-_-\\. | | ) d) The calculated molarity of the vinegar would be smaller than it should be. Some of the NaOH was used to fill the volume of the air bubble. Thus, the recorded volume of NaOH is smaller than it would have been in the absence of an air bubble