ANSWER QUESTION C ONLY

The following is a table to crash a project. (it is an activity on arrow network). The predecessors are defined by the activity arrows. Be sure to complete the crash $ / day in Table 3; otherwise, the remainder of Part II cannot be completed. (2 Points for this part) Activity Arrows Normal Time Normal - $ Crash $ / day Crash Time (days) Crash Time - $ $ (1-2) 6 600 4 1,000 (1-3) 4 600 2 2,000 (2-4) 5 500 3 1,500 (2-5) 3 450 2 550 (3-4) 6 900 4 2,000 (4-6) 8 800 4 3,000 (5-6) 4 400 2 1,000 (6-7) 3 450 2 800 Total 4,700 There are no partial or prohibited crashes in this exercise. Based on the above data provided (this table is all you need), you are being asked to crash this project by three days. Complete the table below to show the crash cost. This is not an activity on node project. a. 2 points: Complete a network diagram (arrow on arrow) for this project network. Nodes are numbered. Show the duration of each activity. b. 4 points: Determine the critical path for the project network. The critical path of the network can be done by making a foward pass and backward pass The forward pass is represented in the first half of every rectangular box and backward pass is mentioned in the second half of the rectangular box of every node as shown below. The critical path represented in the diagram with a double line) C. You are asked to crash this project by three days. The original cost total was based on the expected project duration and includes all costs (both direct and indirect). If a day can be cut from the project, it reduces indirect cost included in the $4,700 by $100 per day. Fill in the remainder of the table not completed; record your information in the table. Note: after the first crash, there will be two critical paths you must deal with. AOA # # Starting Cost before Crash Savings Indirect cost) Crash Cost Adjusted Cost Duration Reduction (Specify Activity Original $4,700 ---- $4,700 O days (4 points) Crash 1 $4,700 ($100) (4 points) Crash 2 (4 points) Crash 3 Note: Adjusted cost = Original cost + Crash Cost-Savings um