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A. Directions: Complete the table below and find the Mean, Variance, and Standard deviation of the following probability distribution. X P(X) X . P(X) X2 X2 . P(X) 92 = [[X2 . P(X)] - 12 1 1/7 192 = - 6 1/7 11 1/7 192 = 16 1/7 92 = (variance) 21 1/7 TOTAL LL= 9 = 9 = (Standard deviation) 2. X P(X) X . P(X) X2 X2 . P(X) 92 = E[X2 . P(X)] - 12 1 3/10 192 = 2 1/10 B 2/10 192 = 4 2/10 94 = (variance) 5 2/10 TOTAL L = 1 = U= (Standard deviation)3 X P(X) X . P(X) X2 X2 . P(X) 92 = [[X2 . P(X)] - 12 3 0.15 92 = 6 0.35 8 0.40 192 = 10 0.10 92 = (variance) TOTAL U = 9 = (Standard deviation) 3 of 44. X P(X) X . P(X) X2 X2 . P(X) 92 = [[X2 . P(X)] - 12 1 4/9 92 = 3 2/9 5 1/9 92 = 7 2/9 192 = (variance) TOTAL LL = 1 =1 19 = (Standard deviation) 5. X P(X) X . P(X) X2 X2 . P(X) 92 = [[X2 . P(X)] - 12 2 0.10 92 = 4 0.23 92 = 6 0.25 8 0.36 292 = (variance) 10 0.06 TOTAL U = 9 = 1 = (Standard deviation)