Answer the following questions concerning the motion interval graph shown below: 0.5 Position 0.4 [Right] 0.3 (m) 0.2 0.1 0 1 2 3 4 5 6 7 8 9 10 Time (s) Select all intervals in which the smart bot is 3 points 0-3 s 3-4 s 4-6 S 6-7 s 7-8 s 8-10 s moving O O O O Right moving O O O O O Left not moving 0 0 0 O O The velocity of the Smarbot from 0.0 to 3.0 s is: 1 point 0.10 m/s [right] 0.17 m/s [right] O 0.30 m/s [right]The velocity of the Smarbot from 4.0 to 6.0 s is: 1 point 0.10 m/s [left] 0.20 m/s [left] 0.30 m/s [left] The total displacement of the Smarbot from 0.0 - 10 s is: 1 point 0.10 m [right] O 0.20 m [right] 0.30 m [right]1. A Cutebot is programmed to increase its [Forward] velocity by 0.40 m/s 1 point each second, for a 5.0 s interval. This means the displacement in each 1.0 s interval will be: O 0.40 m 0.40 m further than the last 1.0 s interval O 0.40 m less than the last 1.0 s interval 2. This Cutebot's velocity, each second, will: 1 point be constant at 0.40 m/s O decrease by 0.40 m/s increase by 0.40 m/sThe graph, below, shows the motion of a different Cutebot for two successive intervals. The Cutebot continues to accelerate for a 3rd second, at the same acceleration rate. 0.35 0.3 0.25 0.2 Position 0.15 [Right] (m) 0.1 0.05 0 0.5 1 1.5 2 2.5 3 3.5 Time (s) 3. Two arrows are placed to show interval displacements. The next 1 point displacement arrow, at 3.0 s, would have a length of: 0.05 m 0.10 m 0.15 m3. Two arrows are placed to show interval displacements. The next 1 point displacement arrow, at 3.0 s, would have a length of: 0.05 m 0.10 m 0.15 m 4. How much does each interval displacement increase, compared to the 1 point second before? O 0.05 m 0.10 m 0.15 m 5. The Cutebots velocity from 2-3 s is: 1 point O 0.15 m/s [Right] 0.20 m /s [Right] 0.30 m /s [Right] 6. The rate of acceleration of the Cutebot is: 1 point 0.050 m/s/s [Right] 0.10 m/s/s [Right] 0.15 m/s/s [Right]