Question: 1. Two liters of a 20% alcohol solution is mixed with x liters of a 50% alcohol solution. if the new mixture contains 38% alcohol,

1. Two liters of a 20% alcohol solution is mixed with x liters of a  50%  alcohol  solution.  if  the  new  mixture  contains  38% alcohol, what is the value of x? 

 
a.  2 L
b.  3 L
c.  4 L
d.  5 L

2. A container holds 3 liters of a 25% alcohol solution. One half liter of the solution is withdrawn and replaced with one half liter of pure alcohol. What is the percentage of alcohol in the new mixture?  


a.  35.7%
b.  53.5%
c.  37.5%
d.  37.37%

Step by Step Solution

3.46 Rating (159 Votes )

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock

mix 2 2 Catarin Solution Z L of celchohol 2001 Alcohed Y 2 381 50 So proportian Y se for every 2... View full answer

blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Mathematics Questions!