Question: answer this Current is passed through a cell where the half-reaction that occurs at the cathode is 5e + Mn04 + 8H* ---->Mn2+ + 4H20.

answer this

Current is passed through a cell where the half-reaction that occurs at the cathode is 5e + Mn04 + 8H* ---->Mn2+ + 4H20. All the Mn04 ions present in 25.0 mL of solution have been reduced after a current of 0.600 ampere has passed for 844 seconds. What was the original concentration of Mn04 ions? A 7.10 ' 10 -3 M B 1.02 ' 10 -1 M 0.21 M D 1.47 M E 4.20 ' 10 -2 M

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