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Recall that there are two apparently different versions of the Wronskian: A. The Wronskian of two solutions y1 (t) and y2 (t) to the second-order linear equation y" + p(t)y' + q(t)y = 0 is defined to be the 2 x 2 yi (t) yz(t) determinant y'(t ) yz (t ) B. The Wronskian of two vector solutions x(1) (t) and x(2) (t) to the two- variable first-order system of linear equations x' (t) = Ax(t) for the 2 x 2 matrix A is defined to be the 2 x 2 determinant | x(1) x(2) |. (Here x(1) (t) and x(2) (t) form the two columns in the determinant.) Further recall that the second-order linear equation can be converted into a two-variable linear system by defining x," (t) = y1(t) and x2 ) ( t ) = yi (t), so x(1) (t) = y1 (t ) Lyi(t ) and similarly for x(2) (t). Prove: the two apparently different notions of the Wronskian are constant multiples of each other, in this case