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If you know that moving a small element of charge dq from one side of the capacitor to the other side against the potential difference V=q/c needs a small amount of work dW. This could be expressed by the following equation dw= (q/c).dq W is the work measured in Joules q is the charge measured in Coulombs C is the capacitance, measured in Farads (i) Formulate a mathematical equation to compute the work accumulated during moving specific number of charges from one plate to the other. Start with uncharged capacitor ((1:0) and put the final charge as variable C1. (ii) Plot the relation between the capacitor charge q, and the capacitor voltage v=q/c. consider c = 1 micro Farad. (iii) Using MATLAB, find the total work needed to charge a 1 micro farad capacitor from 0 to 5 coulom bs numerically using mid-ordinate rule with n = 50