Question: answers for question 2: a) Vx=866 m/s, #2 b)1.28 x 10^4 m 1. A cannon is aimed across Bottomless Gorge at an angle of 22.6
answers for question 2: a) Vx=866 m/s, #2 b)1.28 x 10^4 m

1. A cannon is aimed across Bottomless Gorge at an angle of 22.6" above the horizontal. The mouth of the cannon is 1.00 m above the ground. It shoots a ball whose velocity upon leaving the cannon is 130 m/s. (a) What are the horizontal and vertical components of the initial velocity of the ball? (120 m/s, 50 m/s) (b) What is the velocity of the ball after 2.00 s? (124 m/s [14"]) ( c ) If the ball strikes the other side of the gorge 54.0 m below the rim (55.0 m below the mouth of the cannon), how wide is Bottomless Gorge? (1320 m) 2. A shell is fired from a gun pointing at an angle of 30" above the horizontal. The muzzle velocity is 1.0x10* m/s. (a) What are the horizontal and vertical components of the shell's initial velocity? (867 m/s, 500 m/s) (b) How high will the shell rise above the level of the gun? (1.28x10 m) (c) Assuming that the shell hits the ground on a small hill at the same level as the gun, calculate how far the hill is away from the gun? (8.84x10* m) 3. A ball is fired from a cannon inclined at 36.9 above the horizontal. The speed with which it leaves the barrel is 200 m/'s and the mouth of the cannon is 2.00 m above ground level. Assume level ground. (a) What are the horizontal and vertical components of the initial velocity of the cannon ball? (160 m/s, 120 m/s) Determine the velocity of the cannon ball at t = 6.0 s. (171 m/s [21"]) ( c ) What is the ball's velocity when it reaches its maximum height? (160 m/s) How far down range (from the cannon mouth) does the ball land? (3.9x103 m)
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