Anybody know how to solve using python?

For each of these parts, show the actual code you used to obtain your answer(s). a) Given your jag number is X (6 digits), your birth year is Y, determine the number of digits in X**Y. b) Determine the number of times (together) that 3's and 1's occur in your answer from Part 6a and output that number. Write a function to calculate different means (assuming it is possible with the given inputted parameters: if a is negative and b is positive, you cannot calculate Logarithmic nor Heronia or Geometric and Centroidal and Harmonic may also not be possible) based on this flag called: def my_means(a, b, flag = 'M'): # where possible is 't', if answer has a value and 'f', if not return possible, answer C Centroidal 2(a^2 + ab + b^2)/3(a + b L Logarithmic b - a/ln(b) - ln(a) H Heronia a + Squareroot ab + b/3 G Geometric Squareroot ab A Harmonic 2/ (1/a + a/b) M Mean (a + b)/2 Write a function called Count Doubles(input_int) with the argument being an integer to return an integer showing the number of occurrences that two of the same digit are next to each other ignoring sequences of zeros in input_int. Examples: a. Count Doubles(1234567890) returns 0 b. CountDoubles(111222333444) returns 8 c. Count Doubles(factorial(400)) returns 65