Question: APPENDIX B VERIFICATION MODEL OF A LEADER ELECTION ALGORITHM The model below follows the description of the leader election protocol in a unidirectional ring from

APPENDIX B VERIFICATION MODEL OF A LEADER ELECTION ALGORITHM The model below follows the description of the leader election protocol in a unidirectional ring from [82] as it is discussed and formalized in [63].1 #define N 5/* nr of processes */2 #define I 3/* node given the smallest number */3 #define L 10/* size of buffer (>=2*N)*/45 mtype ={one, two, winner}; /* three symbolic msg names */6 chan q[N]=[L] of {mtype, byte}; /* asynchronous channel */78 byte nr_leaders =0; /* count the number of process that 9 think they are leader of the ring */10 proctype node (chan in, out; byte mynumber)/* process template */11{ bit Active =1, know_winner =0; 12 byte nr, maximum = mynumber, neighbourR; 1314 IEEE TRANSACTIONS ON SOFTWARE ENGINEERING, VOL. 23, NO.5, MAY 1997 J:\PRODUCTION\TSE\2-INPROD\MAY\104928.0\104928_1.DOC regularpaper97.dot S 19,96805/29/974:13 PM 14/14 xr in; /* claim exclusive recv access to channel in */15 xs out; /* claim exclusive send access to channel out */1617 printf(MSC: percentd
, mynumber); 18 out!one(mynumber); /* send msg of type one, with par mynumber */19 end: do 20 :: in?one(nr)->/* receive msg of type one, with par nr */21 if 22 :: Active ->23 if 24 :: nr != maximum ->25 out!two(nr); 26 neighbourR = nr 27 :: else ->28/* max is greatest number */29 assert(nr == N); 30 know_winner =1; 31 out!winner,nr; 32 fi 33 :: else ->34 out!one(nr)35 fi 3637 :: in?two(nr)->38 if 39 :: Active ->40 if 41 :: neighbourR > nr && neighbourR > maximum ->42 maximum = neighbourR; 43 out!one(neighbourR)44 :: else ->45 Active =046 fi 47 :: else ->48 out!two(nr)49 fi 50 :: in?winner,nr ->51 if 52 :: nr != mynumber ->53 printf(MSC: LOST
); 54 :: else ->55 printf(MSC: LEADER
); 56 nr_leaders++; 57 assert(nrleaders ==1)58 fi; 59 if 60 :: know_winner 61 :: else -> out!winner,nr 62 fi; 63 break 64 od 65}6667 init {/* the initial process */68 byte proc; 69 atomic {/* atomically activate N copies of proc template node */70 proc =1; 71 do 72 :: proc <= N ->73 run node (q[proc-1], q[procpercentN],(N+I-proc)percentN+1); 74 proc++75 :: proc > N ->76 break 77 od 78}79} in spin model checker with output screenshots

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