Question: APPLICATION 1 ( Optimization ) : DATA: A homeowner wants to build, along her driveway, a garden surrounded by a fence. If the garden is

APPLICATION 1(Optimization):
DATA:
A homeowner wants to build, along her driveway, a garden surrounded by a fence. If the garden
is to be 1250 square feet, and the fence along the driveway costs $6 per foot while on the other three
sides it costs only $2 per foot, find : Y
a. Find the dimensions that will minimize the fence cost
b. Find the minimum cost.
SOLUTION:
a. Area : x*y=1250ft^(2)
y=(1250)/(x)
C=6y+2x+2x+2y=8x+8y
c(x)=8x+8((1250)/(x))=8x+(10,000)/(x)
(dc)/(dx)=8-(10.000)/(x^(2))=0,x=\sqrt(1250)~~35.36\int (1250)/(x)->(1250)/(35.36)~~35.36
{(:[(10,000)/(x^(2))=8->x^(2)=(10.000)/(8 b. c(x))=8x+(10.000)/(x)=1250,c~~8(35.36)+(10000)/(35.36)=$565.69):}
x~~35.36]
APPLICATION 2(Biomedical):
x~~35.36
y~~35.36
min. cost : $565.69
DATA:
a. If the amount of a drug in a person's blood after t hours is f(t)=3(t)/(t^(2)+9),
when will the drug concentration f(t) be the greatest? ?f(t)=f(max)=.
Solution:
a. f^(')(t)=(3t^(2))/(t^(2)+9)-(6t^(2))/((t^(2)+9)^(2))
(3)/(t^(2)+9)-(6t^(2))/((t^(2)+9)^(2))=0
t=-3,3*0
f(3)=(1)/(2)
greatest concentration: 0.5 e s no
APPLICATION 1 ( Optimization ) : DATA: A

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